I am certainly no expert on statistics and don't claim to understand the laws of convergence or large number theory, but I guess we have shown that the probability starts at 11% for the first egg and approaches 44% (100% x 66% x 66%) as the sample size increases.
Of course, if you hatch an albino, your probabilities change as you are no longer dealing with a conditional probability (prob of both being hets).
Something about this still bugs me from a probabilistic standpoint. The probability of either one NOT being a het is 0.33. So therefore, isn't the probability of not having two hets equal to the probability of one not being het or the other not being het? So the odds of having either snake be a non-het should be 66%.
Therefore 2/3 of the time, you have 0% chance of producing an albino. Then for the other 1/3 of the time, you still only have a 1/4 chance of getting an albino baby from given egg, giving 1/12 probability of having an albino baby? Now I am really confusing myself!
I need to go back and reread my conditional probabilities!
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Chris Harrison