I was told that across the diode i'll have a 1.5 voltage drop. I have 2 volt LED's, so would I calculate this as actually having 3.5 volts per LED? If I would calculate the voltage drop so that it won't power that many LED's, but needs to be cut to keep from overpowering, could I run like 4 LED's, pulling a total of 8 watts, then i'd need to drop the voltage 6 volts? Therefore using around a 535 ohm resistor. This way doing it somewhat along the lines of
S
|
-R-L-L-L-L
| |
-R-L-L-L-L
| |
-R-L-L-L-L
| |
----------
(with the S being power supply, R being resistor, L being LED, and the - and | being the wire runs.)
I'd appreciate it!
Thanks,
-----
-Chris
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