How do you get an albino from 1.1 66% het for albino?
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How do you get an albino from 1.1 66% het for albino?
Prove out your 66% possible hets. What 66% possible het means is that 2 out of 3 babies in that litter are hets and the third is not het but you can not see which ones are so they are all Possible's until you prove them to be hets or not. Hope this clarifies it for you. Good luck Scott Mid Atlantic Morphs
So I would have to breed the two 66% hets that i have. Then take there offspring and do a backcross. and see if i get an albino?
Prove to be het for Albino. By breeding them together you can only prove for sure that they are both hets by getting Albino's in the litter. If you do not get Albino's from this breeding it only means that one is not het but both could be normals. More breeding will tell you if you continue to breed them to definite hets in their next breeding's and prove them one way or another This is the fun part not knowing what you are going to get until they are born good luck Scott
OK I got ya. Thanxs for your help.
To start off when you breed het for Albino to het for Albino you should get Albino's and 66% possible het Albino's. This is where my theory comes in, I think that the 66 percent only applies when you get 25% of the litter as Albino's then the remainder will be normal looking babies which 66% are hets and 33% are normals. Here comes the curve ball to this. Its suppose to work like this, In this breeding each of the parents pass on the Albino gene to 50% of the litter and when any of the babies get this gene from both parents it is an Albino and when any of the babies get this gene from one of the parents it is a het for Albino and when any of the babies does not get the gene from either parent it is a normal. So here we go, Say that you have 20 babies from this breeding (working with known hets) and you do not get Albino's then all the babies are hets this works out to be 100% het. Then in this same breeding you have babies and you get 10 Albino's in 20 babies then all the other babies are normals with no hets this works out to be 0% het. So lets breed them again and you get 2 Albino's in 20 babies to me this means that 14 of the other babies are hets and 2 are normals this works out to be 87% het. So I hope by now you get where I'm going with this, I think that the number of Albino's in the litter determines the percentage of het left in the litter. The Industry standard in this type of breeding is 66% possible hets and we use this when selling babies but if I can I would like to prove this theory let me know what the rest of you think thanks for taking the time to read my ramblings Scott Mid Atlantic Morphs
With a het to het breeding the odds that each individual, normal appearing snake, in the litter will be heterozygous is always 66% for each individual. It does not make any difference how each of the rest of the litter turn out. The 66% possibility applies to each individual in the litter separately. Its like rolling a one-thirds / two-thirds set of dice for each individual in the litter one at a time to determine whether it will be het or not. There is no connection between individual littermates as far as whether they will be homozygous or heterozygous. Additionally, the larger the litter, the closer the numbers will come to the 66% mark. Conversely, I know of one small litter of boids from a het to het breeding that produced 75% albinos. Just my take on it.
Kelly
An interesting theory. You ought to test it. Here's how: Take one six-sided die. Roll it four times -- one roll for each egg in a four-egg clutch.
1 = albino (two albino genes)
2 = heterozygous albino (albino gene from the father and normal gene from the mother)
3 = heterozygous albino (normal gene from the father and albino gene from the mother)
4 = normal (two normal genes)
5 = no meaning, roll again until the result is in the 1-4 range
6 = no meaning, roll again until the result is in the 1-4 range
If the die is balanced on an edge when it stops, the egg contains a dead embryo of unknown genotype. 
Repeat for 50-100 cluches, and report the results here.
Paul Hollander
If the Dice stops balanced on a CORNER, then you find a new, undiscovered morph. 
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Thanks,
Dave "Rainbows-R-Us"
0.1 Wife
0.2 kids
4.12 Brazilian Rainbow Boa
1.0 Hypomelanistic BRB
0.1 Het for Hypomelanistic BRB
0.1 BCI "Elvira" normal from 1989
1.0 BCI albino / het-anery
0.1 BCI Hypo / het-albino
0.1 BCI Anery / het-albino
0.1 BCI Hypo (possible super)
1.0 BCI albino het stripe
1.0 BCI salmon hypo
0.1 BCI ghost
lots.lots.lots feeder mice and rats 
of whether or not you're able to produce albinos depends on the integrity of the person you bought them from. If you bought them directly from a reputable breeder/dealer then they may be legitimate possible hets. There are many scammers out there that would just take normals and SAY they are possible hets just to make a quick buck. Of course there should be no surprise when they don't prove out. Then you figure one or the other wasn't a het and you go on wasting time trying to figure out what's up. I'm not saying this is the case here with your animals. I'm just warning anyone else out there reading this to know who you're buying from when dealing with possible hets because they may not be possible hets at all.
Going to take a gamble on the 66% hets. got a good offer of $250 for 1.1 shipped from Reza Rubyono @ Radreptiles. Grow um and breed and see what i get. Either way for that price i dont loose. Thanks for all yalls help.
I happen to know Reza, and can vouche that his Boas for sale were in fact 66%'ers for Albino. Good luck with them, and let us know the outcome in 3 years.
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--aka DMOG68
Thanks i will do that. but in the mean time does anybody know who sells adult female irian jaya or costal carpet? i got a Barker stock male that is 7 years old and pushing 7 feet with a full vertb. stripe. Cant find an adult female to save my life. any help would be helpful. i need SOMETHING to do while these boas mature
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