Posted by:
Jordan_Russell
at Tue Jan 12 00:44:56 2010 [ Report Abuse ] [ Email Message ] [ Show All Posts by Jordan_Russell ]
"to my understanding, the platty gene almost works like the clark strain albion gene. in where any combination of platty gene is bred to another, it has the possibility of producing any of the three ivory, ultra ivory, or lucy. as ive seen it, a platty x platty has the potential to produce the ivory, ultra ivory, or lucy or any combination of the three"
The two genes express 3 phenotypes, but for two completely different reasons.
I am confident, that through breed trials you will find that particular platinum bloodlines will produce only ultras and subsequently other lines will produce only abus. The two lines crossed will produce only ivories. You will never see 3 phenotypes from a platinum to platinum breeding, only two. You see parent animals can only give one chromosome each to their offspring (diploid organisms). Which means that if one parent is the platinum (visual heterozygous animal) for the Abu line, and other is the platinum for the ultra line and each parent gives one chromosome the offspring will be the inbetween homozygous version = ivory.
The only way you will see three phenotypes is ivory x ivory breedings.
With the Clark strain albinism, there is a modifier gene which controls the amino acid compounds which control the protein which is expressed in lavender and purple is transferred in an incomplete dominant fashion. The albinism itself is obviously simple recessive. I came up with this theory in 2007, subsequently tested by Tim O'Reilly @ Prehistoric Pets through breed trials in 2008 and 2009, and proven without failing both seasons. White X White = White. Lavender X Lavender fruits all three phases. Purple X Purple = Purple. Purple X White = Lavender. White X Lavender = White and Lavenders & Purple X Lavender = Purples and Lavenders.
Regards, Jordan
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