Posted by:
liquidleaf
at Fri Jul 6 08:58:10 2007 [ Email Message ] [ Show All Posts by liquidleaf ]
The two types of albino genes are incompatible.
The results of the two separate gene combinations for het x het are:
1/4 sharp albino 2/4 het sharp albino 1/4 normal
1/4 kahl albino 2/4 het kahl albino 1/4 normal
............
Multiply out all the possible combinations and you get:
1/16 sharp/kahl albino 2/16 sharp albino/ het kahl albino 1/16 sharp albino non-het for kahl
2/16 kahl albino, het sharp albino 4/16 het sharp / het kahl 2/16 het sharp albino non-het for kahl
1/16 kahl albino, not het for sharp 2/16 het kahl albino, not het for sharp 1/16 fully normal, not het for either
........... But, since you won't be able to tell hets from non-hets, you will actually get...
1/16 Kahl/Sharp albino (if these do wind up looking different from plain kahl or sharp albinos) 3/16 Sharp albinos 66% possibly het for kahl 3/16 Kahl albinos, 66% possibly het for sharp 9/16 normal-looking, 66% possibly het for sharp, 66% possibly het for kahl
I might have that last percentage possibility percentage off. But I think the reason no one has really done this yet, ESPECIALLY with two hets, is that it is so hard to keep track of the possible hets. Also, how do you know for sure that one high-conrast Kahl albino isn't actually a Sharp with complete certainty? Sounds like a nightmare to keep track of, though I am curious to see what the complete kahl/sharp albino would look like if the mutations somehow layer on the skin differently. ----- Lauren Madar - OphidiaGems.com | CageMakers 1.0 Ball Python, 1.0 Hog Island Boa (RIP DeeDee), 1.1 Hypo BCI, 1.1 Surinam BCC, 0.1 Green Tree Python
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